How many final states can a dfa have
WebI know a DFA can have multiple accepting states, but can an NFA also have multiple accepting states? finite-automata Share Cite Follow asked Dec 28, 2016 at 10:49 user63810 21 1 2 Add a comment 1 Answer Sorted by: 6 Whenever one is in doubt about central notions, one must consult the definitions of them. Web23 jan. 2015 · 2. There is no requirement that the set of accepting states be non-empty. A DFA must always have an initial state, so the minimum number of states needed to …
How many final states can a dfa have
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Web21 apr. 2010 · The states q3 and q4 are considered final states. This base logic understanding comes from previous examples. Now construct the remaining logic. The … Web21 jun. 2015 · If the n -bit automaton has k states, then the corresponding finite-state automaton has 2 n k states. An automaton that stores m binary words each of length n has a total of mn bits of memory, so each state of the mn -bit automaton corresponds to 2 m n states of the corresponding memoryless finite-state automaton. Share Cite Follow
Web23 jan. 2024 · 1 Answer. Sorted by: 3. It depends on how you're defining Turing Machines - these are theoretical things where the definitions can vary based on what conventions you like to adopt - but you can think of a Turing machine as having accepting states like, e.g., DFAs and PDAs, or as having two fixed states named "halt accept" and "halt reject". Web9 nov. 2024 · 1 Answer Sorted by: 6 The definition of DFAs calls for a set of final (aka accepting) states. Nothing requires that set to be non-empty. But note that a DFA …
Web4 dec. 2024 · How many initial states can a DFA have? DFA can only have one initial state, but can have zero, one or more than one final states over any number of input … Web8 aug. 2024 · Both NFA and DFA have the same power and each NFA can be translated into a DFA. There can be multiple final states in both DFA and NFA. NFA is more of a …
Web2 okt. 2024 · Yes. That one state must be the initial state. If it is also an acceptor state, the DFA accepts the language $\{\epsilon\}$; if not, the DFA accepts the language $\varnothing$. Both of these are languages over any alphabet, including the empty alphabet.
Web30 jan. 2014 · 2. I'm having trouble understanding how to estimate the number of states in the intersection of two DFA's (M1 and M2, which have n and k states). I don't want to construct an actual DFA, but to understand how many states an intersection will give. For example, the union of M1 and M2 will give n x k states (if I have understood this … rawcliffe associates ltdWeb8 aug. 2024 · Both NFA and DFA have the same power and each NFA can be translated into a DFA. There can be multiple final states in both DFA and NFA. NFA is more of a theoretical concept. DFA is used in Lexical … simpleclub ethikWeb5 sep. 2024 · How many different DFAs are there with one state? There are 4 such pairs, each with a binary choice, for a total of 16 transition configurations ( 2^4 = 16 ). There are 2 valid minimal configurations of accepting states (A accepts, B does not; B accepts, A does not). So the maximum value of possible minimal two-state DFAs is 2 * 16 = 32 . rawcliffe associatesWeb6 feb. 2024 · 1 Answer. As pointed out in the comments, finding a DFA for compliment of the language of another DFA is quite straightforward: you simply make all accepting states non-accepting, and vice-versa. The resulting DFA may not be minimal for the language it accepts, but it is still a DFA. You might be thinking of how to find a DFA for the reversal ... rawcliffe avenue yorkWeb4 feb. 2012 · For instance, a minimal DFA for the language {a} over alphabet {a, b} must have 3 states: a start state where you can see a and accept; an accepting state where you reject if you see anything else; and a dead state where you go if you see a b or anything in the accepting state. Never heard of omitting dead states from minimal DFAs. … simpleclub crashkursWebSuppose that I have 2 DFA's and 7 and 6 state respectively, and 3 and 4 final states respectively. If I build the product DFA for the intersection of their languages how many finals states will the resulting DFA have? (a) 12. (b) 9. (c) 3. (d) 1. (e) It cannot be determined from the given information. simpleclub evolutionstheorieWeb11 jul. 2024 · It, as an NFA, has one state (an accepting state), with one transition on a to itself. As a DFA, this has two states: an accepting state and a non-accepting state. On b, there is a transition from the accepting state to the non-accepting state. DFAs need all transitions and all states to be complete, unlike NFAs. – Welbog Jul 25, 2024 at 17:07 simple club englisch simple past